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0.2313x^2+2.600x-49.83=0
a = 0.2313; b = 2.600; c = -49.83;
Δ = b2-4ac
Δ = 2.6002-4·0.2313·(-49.83)
Δ = 52.862716
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.600)-\sqrt{52.862716}}{2*0.2313}=\frac{-2.6-\sqrt{52.862716}}{0.4626} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.600)+\sqrt{52.862716}}{2*0.2313}=\frac{-2.6+\sqrt{52.862716}}{0.4626} $
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